12a^2=20a

Solution for 12a^2=20a equation:

12a^2=20a

We move all terms to the left:

12a^2-(20a)=0

a = 12; b = -20; c = 0;
Δ = b2-4ac
Δ = -202-4·12·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20}{2*12}=\frac{0}{24}
=0
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20}{2*12}=\frac{40}{24}
=1+2/3
$